It might not be so simple as that, but here is a small, easy illustration on how to do that in JavaScript.
/* Example of a set of three numbers */ // Two integers var integerXs: string[]; var integerYs: string[]; var integerZs: string[]; var key: number; set(integerXs, integerYs);
Notice that there is no extra keyword to specify the number to which the key key is assigned. It’s just that two strings are assigned to the keys and each string’s length specifies the number of characters that it contains.
This is what a set of integers looks like as a function call:
function integerXs(n: number): string[] { // key == n return new string[] { ‘one’ }.join(‘ ‘); }
If you want to keep your key constants for a specific number, the JavaScript standard says you may use .length as the key in order to indicate the length of a string. Thus, a key of “two”, for example, could be defined like this:
var integerYs: string[] = { ‘four’ : ” }; function integerZs(n: number): string[] { // key == n = string { // [n] + 1 ‘eight’ : ” }; return new string[] { ‘one’ }; } function integerXs(n: number): string[] { int(n); return new string[] { ‘one’ }; }
You’ll notice that the value of the two strings in the key will be two, and that’s because the values of the strings do not change, even when they are reassigned. If you want to write a function that changes its value, you could do the following:
function integerXs(n: number): string[] { int(n); return new string[] { ‘one’ }; } function integerZs(n: number): string[] { int(n); return new string[] { ‘one’ }; } function stringYs(n: number): string[] { string.length; let key = ‘two’; switch (key) { // case ‘two’ case ‘two’ case ‘four’ case ‘eight’ }; }
JavaScript’s string methods are very concise and easy to use. Here is an example of the following, which prints out the four strings that the function contains:
const stringYs = `$4
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